Subject: i386 endian.h broken with -ansi

From: Jan-Hinrich Fessel <[email-masked]>

Hei out there!

When compiling with -ansi, endian.h is (and thus the host to network order
functons are) broken because of the asm statement, which is not a valid
keyword in GCC -ansi.   Attached a unidiff to fix this bugs, at least for me
it works just fine.

Funny that it never occured to anyone, though.
 
Gruesse
	Oskar

 ==============================================================================
 					Tragbar ist, was nicht herunterfaellt.
						    [email-masked]
 ==============================================================================

--- endian.h-	Mon Jul 18 21:10:46 1994
+++ endian.h	Mon Sep 12 08:18:44 1994
@@ -70,14 +70,14 @@
 #if defined(KERNEL) && !defined(I386_CPU)
 #define __byte_swap_long(x) \
 ({ register unsigned long __x = (x); \
-   asm ("bswap %1" \
+   __asm__ ("bswap %1" \
 	: "=r" (__x) \
 	: "0" (__x)); \
    __x; })
 #else
 #define __byte_swap_long(x) \
 ({ register unsigned long __x = (x); \
-   asm ("rorw $8, %w1\n\trorl $16, %1\n\trorw $8, %w1" \
+   __asm__ ("rorw $8, %w1\n\trorl $16, %1\n\trorw $8, %w1" \
 	: "=r" (__x) \
 	: "0" (__x)); \
    __x; })
@@ -85,7 +85,7 @@
 
 #define __byte_swap_word(x) \
 ({ register unsigned short __x = (x); \
-   asm ("rorw $8, %w1" \
+   __asm__ ("rorw $8, %w1" \
 	: "=r" (__x) \
 	: "0" (__x)); \
    __x; })